Write a function called power that takes double value for n and int value for p and return the result as double. use default argument of 2 for p if this argument is omitted.

#include<iostream.h>

#include<conio.h>

double power (double n,int p=2)

{

int count;

int r=1;

for(count=1;count<=p;count++)

{

r=r*n;

}

return r;

}

int main()

{

double a,b;

int c;

clrscr();

cout<<"Enter no.";

cin>>a;

cout<<"Enter power";

cin>>c;

b=power(a,c);

cout<<"Result="<<b;

return 0;

}

  

Output

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